Optimal. Leaf size=140 \[ -\frac{c^2 (6 b B-A c) \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{b x^2+c x^4}}\right )}{16 b^{3/2}}-\frac{\left (b x^2+c x^4\right )^{3/2} (6 b B-A c)}{24 b x^7}-\frac{c \sqrt{b x^2+c x^4} (6 b B-A c)}{16 b x^3}-\frac{A \left (b x^2+c x^4\right )^{5/2}}{6 b x^{11}} \]
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Rubi [A] time = 0.223342, antiderivative size = 140, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.154, Rules used = {2038, 2020, 2008, 206} \[ -\frac{c^2 (6 b B-A c) \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{b x^2+c x^4}}\right )}{16 b^{3/2}}-\frac{\left (b x^2+c x^4\right )^{3/2} (6 b B-A c)}{24 b x^7}-\frac{c \sqrt{b x^2+c x^4} (6 b B-A c)}{16 b x^3}-\frac{A \left (b x^2+c x^4\right )^{5/2}}{6 b x^{11}} \]
Antiderivative was successfully verified.
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Rule 2038
Rule 2020
Rule 2008
Rule 206
Rubi steps
\begin{align*} \int \frac{\left (A+B x^2\right ) \left (b x^2+c x^4\right )^{3/2}}{x^{10}} \, dx &=-\frac{A \left (b x^2+c x^4\right )^{5/2}}{6 b x^{11}}-\frac{(-6 b B+A c) \int \frac{\left (b x^2+c x^4\right )^{3/2}}{x^8} \, dx}{6 b}\\ &=-\frac{(6 b B-A c) \left (b x^2+c x^4\right )^{3/2}}{24 b x^7}-\frac{A \left (b x^2+c x^4\right )^{5/2}}{6 b x^{11}}+\frac{(c (6 b B-A c)) \int \frac{\sqrt{b x^2+c x^4}}{x^4} \, dx}{8 b}\\ &=-\frac{c (6 b B-A c) \sqrt{b x^2+c x^4}}{16 b x^3}-\frac{(6 b B-A c) \left (b x^2+c x^4\right )^{3/2}}{24 b x^7}-\frac{A \left (b x^2+c x^4\right )^{5/2}}{6 b x^{11}}+\frac{\left (c^2 (6 b B-A c)\right ) \int \frac{1}{\sqrt{b x^2+c x^4}} \, dx}{16 b}\\ &=-\frac{c (6 b B-A c) \sqrt{b x^2+c x^4}}{16 b x^3}-\frac{(6 b B-A c) \left (b x^2+c x^4\right )^{3/2}}{24 b x^7}-\frac{A \left (b x^2+c x^4\right )^{5/2}}{6 b x^{11}}-\frac{\left (c^2 (6 b B-A c)\right ) \operatorname{Subst}\left (\int \frac{1}{1-b x^2} \, dx,x,\frac{x}{\sqrt{b x^2+c x^4}}\right )}{16 b}\\ &=-\frac{c (6 b B-A c) \sqrt{b x^2+c x^4}}{16 b x^3}-\frac{(6 b B-A c) \left (b x^2+c x^4\right )^{3/2}}{24 b x^7}-\frac{A \left (b x^2+c x^4\right )^{5/2}}{6 b x^{11}}-\frac{c^2 (6 b B-A c) \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{b x^2+c x^4}}\right )}{16 b^{3/2}}\\ \end{align*}
Mathematica [A] time = 0.127024, size = 121, normalized size = 0.86 \[ -\frac{\left (b+c x^2\right ) \left (A \left (8 b^2+14 b c x^2+3 c^2 x^4\right )+6 b B x^2 \left (2 b+5 c x^2\right )\right )+3 c^2 x^6 \sqrt{\frac{c x^2}{b}+1} (6 b B-A c) \tanh ^{-1}\left (\sqrt{\frac{c x^2}{b}+1}\right )}{48 b x^5 \sqrt{x^2 \left (b+c x^2\right )}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.013, size = 259, normalized size = 1.9 \begin{align*}{\frac{1}{48\,{x}^{9}{b}^{3}} \left ( c{x}^{4}+b{x}^{2} \right ) ^{{\frac{3}{2}}} \left ( 3\,A{b}^{3/2}\ln \left ( 2\,{\frac{\sqrt{b}\sqrt{c{x}^{2}+b}+b}{x}} \right ){x}^{6}{c}^{3}-A \left ( c{x}^{2}+b \right ) ^{{\frac{3}{2}}}{x}^{6}{c}^{3}-18\,B{b}^{5/2}\ln \left ( 2\,{\frac{\sqrt{b}\sqrt{c{x}^{2}+b}+b}{x}} \right ){x}^{6}{c}^{2}+6\,B \left ( c{x}^{2}+b \right ) ^{3/2}{x}^{6}b{c}^{2}+A \left ( c{x}^{2}+b \right ) ^{{\frac{5}{2}}}{x}^{4}{c}^{2}-3\,A\sqrt{c{x}^{2}+b}{x}^{6}b{c}^{3}-6\,B \left ( c{x}^{2}+b \right ) ^{5/2}{x}^{4}bc+18\,B\sqrt{c{x}^{2}+b}{x}^{6}{b}^{2}{c}^{2}+2\,A \left ( c{x}^{2}+b \right ) ^{5/2}{x}^{2}bc-12\,B \left ( c{x}^{2}+b \right ) ^{5/2}{x}^{2}{b}^{2}-8\,A \left ( c{x}^{2}+b \right ) ^{5/2}{b}^{2} \right ) \left ( c{x}^{2}+b \right ) ^{-{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (c x^{4} + b x^{2}\right )}^{\frac{3}{2}}{\left (B x^{2} + A\right )}}{x^{10}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.16548, size = 549, normalized size = 3.92 \begin{align*} \left [-\frac{3 \,{\left (6 \, B b c^{2} - A c^{3}\right )} \sqrt{b} x^{7} \log \left (-\frac{c x^{3} + 2 \, b x + 2 \, \sqrt{c x^{4} + b x^{2}} \sqrt{b}}{x^{3}}\right ) + 2 \,{\left (3 \,{\left (10 \, B b^{2} c + A b c^{2}\right )} x^{4} + 8 \, A b^{3} + 2 \,{\left (6 \, B b^{3} + 7 \, A b^{2} c\right )} x^{2}\right )} \sqrt{c x^{4} + b x^{2}}}{96 \, b^{2} x^{7}}, \frac{3 \,{\left (6 \, B b c^{2} - A c^{3}\right )} \sqrt{-b} x^{7} \arctan \left (\frac{\sqrt{c x^{4} + b x^{2}} \sqrt{-b}}{c x^{3} + b x}\right ) -{\left (3 \,{\left (10 \, B b^{2} c + A b c^{2}\right )} x^{4} + 8 \, A b^{3} + 2 \,{\left (6 \, B b^{3} + 7 \, A b^{2} c\right )} x^{2}\right )} \sqrt{c x^{4} + b x^{2}}}{48 \, b^{2} x^{7}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (x^{2} \left (b + c x^{2}\right )\right )^{\frac{3}{2}} \left (A + B x^{2}\right )}{x^{10}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.32323, size = 236, normalized size = 1.69 \begin{align*} \frac{\frac{3 \,{\left (6 \, B b c^{3} \mathrm{sgn}\left (x\right ) - A c^{4} \mathrm{sgn}\left (x\right )\right )} \arctan \left (\frac{\sqrt{c x^{2} + b}}{\sqrt{-b}}\right )}{\sqrt{-b} b} - \frac{30 \,{\left (c x^{2} + b\right )}^{\frac{5}{2}} B b c^{3} \mathrm{sgn}\left (x\right ) - 48 \,{\left (c x^{2} + b\right )}^{\frac{3}{2}} B b^{2} c^{3} \mathrm{sgn}\left (x\right ) + 18 \, \sqrt{c x^{2} + b} B b^{3} c^{3} \mathrm{sgn}\left (x\right ) + 3 \,{\left (c x^{2} + b\right )}^{\frac{5}{2}} A c^{4} \mathrm{sgn}\left (x\right ) + 8 \,{\left (c x^{2} + b\right )}^{\frac{3}{2}} A b c^{4} \mathrm{sgn}\left (x\right ) - 3 \, \sqrt{c x^{2} + b} A b^{2} c^{4} \mathrm{sgn}\left (x\right )}{b c^{3} x^{6}}}{48 \, c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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